Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Jump to bottom

fix(core)!: $(...).[last,first,all]() defaulting to the first output instead of the output that connects the nodes #9760

Merged
merged 3 commits into from
Jun 19, 2024
Merged

fix(core)!: $(...).[last,first,all]() defaulting to the first output instead of the output that connects the nodes #9760

Changes from 1 commit
Commits
Show all changes
3 commits
Select commit Hold shift + click to select a range
fa67ebf
fix(core): `$(...).[last,first,all]()` defaulting to the first output…
despairblue Jun 14, 2024
4f83349
document breaking changes
despairblue Jun 18, 2024
b8db4f7
update version number
despairblue Jun 19, 2024
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
12 changes: 12 additions & 0 deletions packages/cli/BREAKING-CHANGES.md
View file
Open in desktop
Original file line number Diff line number Diff line change
Expand Up @@ -2,6 +2,18 @@

This list shows all the versions which include breaking changes and how to upgrade.

## 1.46.0
despairblue marked this conversation as resolved.
Show resolved Hide resolved

### What changed?

Calling `$(...).last()` (or `$(...).first()` or `$(...).all()` respectively) without arguments is returning the the last item (or first or all items) of the output that connects the two nodes. Before it was returning the item/items of the first output of that node.

### When is action necessary?

If you are using `$(...).last()` (or `$(...).first()` or `$(...)all()` respectively) without arguments for nodes that have multiple outputs (e.g. `If`, `Switch`, `Compare Datasets`, etc.) and you want it to default to the first output. In that case change it to `$(...).last(0)` (or `first` or `all` respectively).

This does not affect the Array functions `[].last()`, `[].first()`.

## 1.40.0

### What changed?
Expand Down
Loading