-
Notifications
You must be signed in to change notification settings - Fork 21
/
GroupAnagrams.js
64 lines (56 loc) 路 1.23 KB
/
GroupAnagrams.js
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
/**
* Given an array of strings, group anagrams together.
*
* For example, given: ["eat", "tea", "tan", "ate", "nat", "bat"],
* Return:
*
* [
* ["ate", "eat","tea"],
* ["nat","tan"],
* ["bat"]
* ]
* Note: All inputs will be in lower-case.
*
* Accepted.
*/
/**
* @param {string[]} strs
* @return {string[][]}
*/
let groupAnagrams = function (strs) {
let results = [];
if (strs.length === 0) {
return results;
}
let map = new Map();
strs.forEach(function (s) {
let chars = s.split('');
chars.sort();
let key = chars.join('');
if (map.get(key) == null) {
map.set(key, []);
}
map.get(key).push(s);
});
map.forEach(function (value, key, map) {
results.push(value);
});
return results;
};
if (groupAnagrams([]).length === 0) {
console.log("pass")
} else {
console.error("failed")
}
let list0 = groupAnagrams(["eat", "tea", "tan", "ate", "nat", "bat"]);
let set = new Set([["ate", "eat", "tea"], ["nat", "tan"], ["bat"]]);
if (list0.length === 3) {
console.log("pass")
} else {
console.error("failed")
}
if (new Set(list0).toString() === set.toString()) {
console.log("pass")
} else {
console.error("failed")
}